0=x^2-3x-14

Solution for 0=x^2-3x-14 equation:

0=x^2-3x-14

We move all terms to the left:

0-(x^2-3x-14)=0

We add all the numbers together, and all the variables

-(x^2-3x-14)=0

We get rid of parentheses

-x^2+3x+14=0

We add all the numbers together, and all the variables

-1x^2+3x+14=0

a = -1; b = 3; c = +14;
Δ = b2-4ac
Δ = 32-4·(-1)·14
Δ = 65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{65}}{2*-1}=\frac{-3-\sqrt{65}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{65}}{2*-1}=\frac{-3+\sqrt{65}}{-2}
$